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how many kilograms of limestone should be added for every kilogram of iron ore processed in a blast furnace if the Can anyone help me answer this ethiopianembassy.za According to …
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4 kgs Solution The correct option is D 4 kgs Answer = Option d For all alligation questions, remember that we need to consider only the cost price Given that the Selling Price = . Cost price×1.1= Selling price Cost price = Selling price 1.1 = …
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Therefore, we will find out how much limestone is required. No, When 95.5 Calcium carbonate is required. We need 100. That means if 95.5 kg of calcium content is required. We need 200 kg …
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Mass of Limestone, in kilograms, should be added for 1.00 kilogram of iron ore processed in a blast furnace with the limestone is 95.5 % CaCO 3 and the iron ore contains 6.78 % SiO 2, …
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Therefore, 200 kilograms of pure water must be added to 100 kilograms of a 30% saline solution to make it a 10% saline solution. Note: In this question, one might make a silly mistake while comparing 10% and ( 30 100 + x × 100) . While comparing these two, one might take the equation as 10 and then solve it as 10 100 = ( 30 100 + x × 100) .
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See the answer What mass of limestone, in kilograms, should be added for 1.00 kilogram of iron ore processed in a blast furnace if the limestone is 95.5 % CaCO 3 and the iron ore contains 7.88 % SiO 2? The resulting product, calcium silicate, …
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39Superflex Wide Joint Grout Line 10 Kg 39 is from the House or the lack of spellcheck can all add up to multiple mistakes that … King Line Screenings 30 KG The Home Depot Canada Create a level base for interlocking and patio slabs Use KING Line Screenings 3 16 inch 5 mm screens which allow for quick construction …
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In order to determine the amount of nickel that must be added to 1.75 kg Ni, it is necessary to use Equation 4.3a.If we letmNirepresent the mass of nickel required, then Equation 4.3a takes the form 43 wt% Ni=mNi1.75 kg+mNi× 100 And solving this expression formNileads tomNi = 1.32 kg
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111.8 grams Fe ÷ 159.8 Fe2O3 grams = .6996 = 69.96% Fe in Fe2O3 Then we apply this percentage to 639 kg. The thought process is as follows: if there is 69.96% of iron in Fe2O3 by weight, then...
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How many kilograms of limestone should be added for every kilogram of iron ore processed in a blast furnace if the limestone is 93.80% pure and the iron ore contains 12.00% SiO 2 by mass? (Note: SiO 2 (s) + CaCO 3 (s) → CaSiO 3 (s) + CO 2 (g)) Submitted by chemistry123 on Fri, 10/12/2012 - 10:42.
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Answer (1 of 2): Percentage by mass of Aluminum in Al2O3 is : % by mass = molar mass Al(2)/ molar mass Al2O3 x 100 % by mass = 2(27)/102 x 100 % by mass = 53% of Al in Al2O3 53% of 712 kg = (.53)(712) = 377 kg of Al from the ore Al2O3
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We can also look at the relationship of Fe with Fe2O3. In one mole of Fe2O3, there are two moles of Fe atoms. First, convert the mass of ore in grams. We know that 1000 grams = 1kg, therefore 639 ...
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The distances to the average in the middle are 40 and 20, so that's the ratio of our two components. We're using more of the $420 component (400 is closer to 420 than to 360), so the ratio of the expensive component to the cheap one is 40 to 20, or 10 to 5, so we're using 5 kg of the cheap component. gmatclubot
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Suppose you need to build a crushed limestone driveway for a friend. Her driveway measures 3 meters wide by 10 meters long, and she wants her driveway to have its final layer to be 10 centimeters (0.1 meters) deep of crushed limestone rocks with a density of 2,410 kg/m³.Let's say you want to consider a 10% wastage percentage for this project. Let us now …
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Total cost for 20kg = 20 × 70.75 = 1415 Adding both, 2100 + 1415 = 3515 Cost Price = 3515 After mixing both, total kg is 50 Each kh costs 80.5 Total cost is 80.5 × 50 = 4025 Selling price = 4025 Gain = selling price — cost price Gain = 4025 —3515 Gain = 510 Answer: 510 3 Sponsored by PEDATICVC - Clearance Sales
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How many kilograms of limestone should be added for every kilogram of iron ore processed in a blast furnace if the limestone is 95.00% pure and the iron ore contains 13.40% SiO2 by …
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nickel must be added to 5.43 kg of copper to yield a solidus temperature of 1200°C?
(Hint, See figure 9.3 and Equation 4.3a) callister 9th edition introduction to materials Science
How many kilograms of pure H 2 S O 4 could be obtained from 1 kg of iron pyrites (F e S 2 ) according to the following reactions? 4 F e S 2 + 1 1 O 2 → 2 F e 2 O 3 + 8 S O 2 2 S O 2 + O 2 → 2 S O 3 S O 3 + H 2 O → H 2 S O 4
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Let x kg of tea worth Rs.300 be added, Quantity of tea taken that was worth Rs.240 =10 kg Total quantity of tea that will be produced after mix= (10+x) kg From the above data, the required equation can be formed as, Solving the above, we get x=5. Ans:- 5kg of tea worth Rs.300 would serve the purpose. Hope this answers your question!
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So we know that we're starting with one kilogram of limestone. Now I want to convert kilograms two grams. So then we can take advantage of the more masses. Now we can …
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Here, approximately, is how much limestone you'll need to raise 1.0 pH level for every 1,000 square feet for the different soil types: Sand: 25 pounds. Loam: 75 pounds. Clay: 100 pounds. These amounts can vary pending other factors in the soil. This may seem like a complicated process, but your fields, lawn or garden will improve the ...
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Let the quantity of Rs.5.4 per kg rice = x kg According to the question, x × 5.4 + 4.5 × 10 = 5.94 × (10 + x) ÷ 120 × 100 5.4x + 45 = 4.95 × (10 + x) 5.4x + 45 = 49.5 + 4.95x 5.4x – 4.95x = 49.5 – 45 0.45x = 4.5 x = 10 kg Hence, option B is correct. Upvote Reply View courses related to this question Explore CLAT courses
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You need 530 kg of limestone to neutralize the lake. > Step 1. Calculate the concentration of H⁺ ["H"^+] = 10^("-pH")" mol/L" =10^-5.6" mol/L" = 2.5 × 10^-6" mol/L" Step 2. Calculate the moles of H⁺ Moles = 4.2 ×10^9" L" × (2.5 × 10^-6" mol")/"1 L" = 1.05 × 10^4" mol" Step 3. Calculate the mass of CaCO₃ CaCO₃ + 2H⁺ → Ca²⁺ + H₂O + CO₂ Mass of CaCO₃ = …
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What mass of limestone, in kilograms, should be added for 1.00 kilogram of iron ore processed in a blast furnace if the limestone is 95.5 % CaCO3 and the iron ore contains …
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How many Kilograms of iron can be recovered from 639 kilograms of the ore Fe2O3? - MW Fe2O3 = 55.82 + 16.03 = 159.6 g ... There are 446.8 kg of iron in 639 kg of iron ore. Some pretty good arguments. Leave a Reply Cancel reply. Your email address will …
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See the answer What mass of limestone, in kilograms, should be added for 1.00 kilogram of iron ore processed in a blast furnace if the limestone is 95.5 % CaCO 3 and the iron ore …
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(5 ratings) Answer. Step 1 Explanation :- Given :- Mass of Iron ore = 1.00 kg % SiO2 in iron ore = 6.78 % % CaCO3 in Limestone = 95.5% Mass of Limestone = ? We have, Molar Mass of …
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The mixture to be produced is of Rs 260 per kg Total quantity of tea that will be produced after mix= (10+x) kg From the given data the equation can be written as 300x + 240 (10) = 260 (10+x) 300x + 2400= 260x + 2600 40x = 200 X= 5 Solving the above, we get x=5. 5kg of tea worth Rs.300 Was this answer helpful? 2.5 (3) (4) (1)
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